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<rss xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title>Lint - Latest Comments in #337 &amp;#8211; Wherein Al&amp;#8217;bert subtly gains the upper hand</title><link>http://colbycheese.disqus.com/</link><description></description><atom:link href="https://colbycheese.disqus.com/05302008/latest.rss" rel="self"></atom:link><language>en</language><lastBuildDate>Fri, 10 Jun 2011 21:31:08 -0000</lastBuildDate><item><title>Re: #337 &amp;#8211; Wherein Al&amp;#8217;bert subtly gains the upper hand</title><link>http://www.colbyfromage.com/lint/2008/05/30/05302008/#comment-223498646</link><description>&lt;p&gt;Or, actually, I wrote that wrong. Log (base 42) of x is equal to f(x) times negative infinity plus one. Whatevs.&lt;/p&gt;</description><dc:creator xmlns:dc="http://purl.org/dc/elements/1.1/">Lenaru</dc:creator><pubDate>Fri, 10 Jun 2011 21:31:08 -0000</pubDate></item><item><title>Re: #337 &amp;#8211; Wherein Al&amp;#8217;bert subtly gains the upper hand</title><link>http://www.colbyfromage.com/lint/2008/05/30/05302008/#comment-223494955</link><description>&lt;p&gt;I must run calculations.&lt;/p&gt;&lt;p&gt;Following the precept that "the bigger they are the harder they fall," also Napoleon, I would assume that this follows the model of an exponential equation. If f(x) equals the force of the fall and x equals "bigness" in awesomeness points, then the function of x is equal to 42 to the xth power times negative infinity plus one. Thus, if you were originally as low as Al'bert, you fall up. This is my postulate. (nod nod)&lt;/p&gt;</description><dc:creator xmlns:dc="http://purl.org/dc/elements/1.1/">Lenaru</dc:creator><pubDate>Fri, 10 Jun 2011 21:19:25 -0000</pubDate></item></channel></rss>